JEE Main 20249 Apr, Morning shiftPhysicsMediumElectrostatics167× since 2002At the centre of a half ring of radius R=10 cm\mathrm{R}=10 \mathrm{~cm}R=10 cm and linear charge density 4 nC m−14 \mathrm{~nC} \mathrm{~m}^{-1}4 nC m−1, the potential is xπVx \pi \mathrm{V}xπV. The value of xxx is _________.Your answerType your answer. Integers and decimals are accepted.CheckSkip · show solution