At any instant the velocity of a particle of mass 500 ~g is (2 t i+3 t² j) ms⁻¹. If the force acting on the particle at t=1 ~s is (i+x j) N. Then the value of x will be:

Laws of Motion: JEE Main 2023 Physics question

JEE Main 2023 · 8 Apr, Morning shift · Q7598

JEE Main 20238 Apr, Morning shiftPhysicsMediumLaws of Motion70× since 2002

At any instant the velocity of a particle of mass

500 \mathrm{~g}

\left(2 t \hat{i}+3 t^{2} \hat{j}\right) \mathrm{ms}^{-1}

. If the force acting on the particle at

t=1 \mathrm{~s}

(\hat{i}+x \hat{j}) \mathrm{N}

. Then the value of

x

will be: