JEE Main 20264 Apr, Evening shiftPhysicsEasyLaws of Motion70× since 2002At t=0t=0t=0, a body of mass 100 g starts moving under the influence of a force (5i^+10j^)(5\hat i+10\hat j)(5i^+10j^) N. After 2 s its position is (2xi^+5yj^)(2x\hat i+5y\hat j)(2xi^+5yj^) m. The ratio x:yx:yx:y is ______.AOption A. 1 : 2BOption B. 2 : 5COption C. 5 : 2DOption D. 5 : 4CheckSkip · show solution