JEE Main 2006Annual, Paper 1MathematicsEasyLimit, Continuity and Differentiability420× since 2002Angle between the tangents to the curve y=x2−5x+6y = {x^2} - 5x + 6y=x2−5x+6 at the points (2,0)(2,0)(2,0) and (3,0)(3,0)(3,0) isAOption A. π\piπBOption B. π2{\pi \over 2}2πCOption C. π6{\pi \over 6}6πDOption D. π4{\pi \over 4}4πCheckSkip · show solution