An expression of energy density is given by u=(α)/(β) sin ((α x)/(k t)), where α, β are constants, x is displacement, k is Boltzmann constant and t is the temperature. The dimensions of β will be:

Units and Measurements: JEE Main 2022 Physics question

JEE Main 2022 · 27 Jul, Evening shift · Q8260

JEE Main 202227 Jul, Evening shiftPhysicsEasyUnits and Measurements122× since 2002

An expression of energy density is given by

u=\frac{\alpha}{\beta} \sin \left(\frac{\alpha x}{k t}\right)

, where

\alpha, \beta

are constants,

x

is displacement,

k

is Boltzmann constant and t is the temperature. The dimensions of

\beta

will be :

JEE Main 2022 Units and Measurements Question with Solution (27 Jul Evening shift, Q8260) | JEE Arc