An electric field, E=(2 i+6 j+8 k)/(√(6)) passes through the surface of 4 ~m² area having unit vector n=((2 i+j+k)/(√(6))). The electric flux for that surface is _ _ _ _ V m.

Electrostatics: JEE Main 2024 Physics question

JEE Main 2024 · 8 Apr, Morning shift · Q57

JEE Main 20248 Apr, Morning shiftPhysicsMediumElectrostatics167× since 2002

An electric field,

\overrightarrow{\mathrm{E}}=\frac{2 \hat{i}+6 \hat{j}+8 \hat{k}}{\sqrt{6}}

passes through the surface of

4 \mathrm{~m}^2

area having unit vector

\hat{n}=\left(\frac{2 \hat{i}+\hat{j}+\hat{k}}{\sqrt{6}}\right)

. The electric flux for that surface is _________

\mathrm{Vm}

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2024 Electrostatics Question with Answer (8 Apr Morning shift, Q57) | JEE Arc