JEE Main 202429 Jan, Evening shiftPhysicsEasyElectrostatics167× since 2002An electric field is given by (6i^+5j^+3k^)N/C(6 \hat{i}+5 \hat{j}+3 \hat{k}) \mathrm{N} / \mathrm{C}(6i^+5j^+3k^)N/C. The electric flux through a surface area 30i^ m230 \hat{i} \mathrm{~m}^230i^ m2 lying in YZ-plane (in SI unit) is :AOption A. 60BOption B. 90COption C. 180DOption D. 150CheckSkip · show solution
