Electrostatics: JEE Main 2020 Physics question

JEE Main 2020 · 9 Jan, Morning shift · Q6943

JEE Main 20209 Jan, Morning shiftPhysicsMediumElectrostatics167× since 2002

An electric dipole of moment

\overrightarrow p = \left( { - \widehat i - 3\widehat j + 2\widehat k} \right) \times {10^{ - 29}}

C.m is at the origin (0, 0, 0). The electric field due to this dipole at

\overrightarrow r = + \widehat i + 3\widehat j + 5\widehat k

(note that

\overrightarrow r .\overrightarrow p = 0

) is parallel to :

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