An astronaut takes a ball of mass m from earth to space. He throws the ball into a circular orbit about earth at an altitude of 318.5 ~km. From earth's surface to the orbit, the change in total mechanical energy of the ball is x (GM e m)/(21 R e). The value of x is (take R e =6370 ~km):

Gravitation: JEE Main 2024 Physics question

JEE Main 2024 · 9 Apr, Morning shift · Q7222

JEE Main 20249 Apr, Morning shiftPhysicsMediumGravitation159× since 2002

An astronaut takes a ball of mass

m

from earth to space. He throws the ball into a circular orbit about earth at an altitude of

318.5 \mathrm{~km}

. From earth's surface to the orbit, the change in total mechanical energy of the ball is

x \frac{\mathrm{GM}_{\mathrm{e}} \mathrm{m}}{21 \mathrm{R}_{\mathrm{e}}}

. The value of

x

is (take

\mathrm{R}_{\mathrm{e}}=6370 \mathrm{~km})

JEE Main 2024 Gravitation Question with Solution (9 Apr Morning shift, Q7222) | JEE Arc