An alternating emf E=440 sin 100 π t is applied to a circuit containing an inductance of (√(2))/(π) H. If an a.c. ammeter is connected in the circuit, its reading will be:

Electromagnetic Induction and Alternating Currents: JEE Main 2022 Physics question

JEE Main 2022 · 29 Jul, Morning shift · Q5912

JEE Main 202229 Jul, Morning shiftPhysicsEasyElectromagnetic Induction and Alternating Currents149× since 2002

An alternating emf

\mathrm{E}=440 \sin 100 \pi \mathrm{t}

is applied to a circuit containing an inductance of

\frac{\sqrt{2}}{\pi} \mathrm{H}

. If an a.c. ammeter is connected in the circuit, its reading will be :

JEE Main 2022 · 29 Jul, Morning shift · Q5912

JEE Main 202229 Jul, Morning shiftPhysicsEasyElectromagnetic Induction and Alternating Currents149× since 2002

An alternating emf

\mathrm{E}=440 \sin 100 \pi \mathrm{t}

is applied to a circuit containing an inductance of

\frac{\sqrt{2}}{\pi} \mathrm{H}

. If an a.c. ammeter is connected in the circuit, its reading will be :