An air bubble of volume 1 ~cm³ rises from the bottom of a lake 40 ~m deep to the surface at a temperature of 12^(°) C. The atmospheric pressure is 1 × 10⁵ ~Pa the density of water is 1000 ~kg / m³ and g=10 ~m / s². There is no difference of the temperature of water at the depth of 40 ~m and on the surface. The volume of air bubble when it reaches the surface will be:

Properties of Solids and Liquids: JEE Main 2023 Physics question

JEE Main 2023 · 8 Apr, Morning shift · Q8029

JEE Main 20238 Apr, Morning shiftPhysicsHardProperties of Solids and Liquids184× since 2002

An air bubble of volume

1 \mathrm{~cm}^{3}

rises from the bottom of a lake

40 \mathrm{~m}

deep to the surface at a temperature of

12^{\circ} \mathrm{C}

. The atmospheric pressure is

1 \times 10^{5} \mathrm{~Pa}

the density of water is

1000 \mathrm{~kg} / \mathrm{m}^{3}

and

\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}

. There is no difference of the temperature of water at the depth of

40 \mathrm{~m}

and on the surface. The volume of air bubble when it reaches the surface will be:

JEE Main 2023 Properties of Solids and Liquids Question with Solution (8 Apr Morning shift, Q8029) | JEE Arc