JEE Main 202117 Mar, Morning shiftPhysicsEasyElectromagnetic Induction and Alternating Currents149× since 2002An AC current is given by I = I₁ sinω\omegaωt + I₂ cosω\omegaωt. A hot wire ammeter will give a reading :AOption A. I1+I22{{{I_1} + {I_2}} \over {\sqrt 2 }}2I1+I2BOption B. I12−I222\sqrt {{{I_1^2 - I_2^2} \over 2}}2I12−I22COption C. I12+I222\sqrt {{{I_1^2 + I_2^2} \over 2}}2I12+I22DOption D. I1+I222{{{I_1} + {I_2}} \over {2\sqrt 2 }}22I1+I2CheckSkip · show solution
