JEE Main 202312 Apr, Morning shiftMathematicsMediumMathematical Reasoning115× since 2008Among the two statements (S1):(p⇒q)∧(p∧(∼q))(\mathrm{S} 1):(p \Rightarrow q) \wedge(p \wedge(\sim q))(S1):(p⇒q)∧(p∧(∼q)) is a contradiction and (S2):(p∧q)∨((∼p)∧q)∨(p∧(∼q))∨((∼p)∧(∼q))(\mathrm{S} 2):(p \wedge q) \vee((\sim p) \wedge q) \vee(p \wedge(\sim q)) \vee((\sim p) \wedge(\sim q))(S2):(p∧q)∨((∼p)∧q)∨(p∧(∼q))∨((∼p)∧(∼q)) is a tautologyAOption A. both are false.BOption B. only (S1) is true.COption C. both are true.DOption D. only (S2) is true.CheckSkip · show solution
