JEE Main 20236 Apr, Evening shiftMathematicsMediumMathematical Reasoning115× since 2008Among the statements (S1) : (p⇒q)∨((∼p)∧q)(p \Rightarrow q) \vee((\sim p) \wedge q)(p⇒q)∨((∼p)∧q) is a tautology (S2) : (q⇒p)⇒((∼p)∧q)(q \Rightarrow p) \Rightarrow((\sim p) \wedge q)(q⇒p)⇒((∼p)∧q) is a contradictionAOption A. neither (S1) and (S2) is TrueBOption B. only (S2) is TrueCOption C. both (S1)(\mathrm{S} 1)(S1) and (S2)(\mathrm{S} 2)(S2) are TrueDOption D. only (S1) is TrueCheckSkip · show solution
