JEE Main 202330 Jan, Morning shiftMathematicsMediumMathematical Reasoning115× since 2008Among the statements : (S1) ((p∨q)⇒r)⇔(p⇒r)(\mathrm{S} 1)~((\mathrm{p} \vee \mathrm{q}) \Rightarrow \mathrm{r}) \Leftrightarrow(\mathrm{p} \Rightarrow \mathrm{r})(S1) ((p∨q)⇒r)⇔(p⇒r) (S2) ((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))(\mathrm{S} 2)~((\mathrm{p} \vee \mathrm{q}) \Rightarrow \mathrm{r}) \Leftrightarrow((\mathrm{p} \Rightarrow \mathrm{r}) \vee(\mathrm{q} \Rightarrow \mathrm{r}))(S2) ((p∨q)⇒r)⇔((p⇒r)∨(q⇒r))AOption A. only (S1) is a tautologyBOption B. neither (S1) nor (S2) is a tautologyCOption C. both (S1) and (S2) are tautologiesDOption D. only (S2) is a tautologyCheckSkip · show solution
