JEE Main 201910 Apr, Morning shiftMathematicsEasyComplex Numbers and Quadratic Equations264× since 2002All the pairs (x, y) that satisfy the inequality 2sin2x−2sinx+5.14sin2y≤1{2^{\sqrt {{{\sin }^2}x - 2\sin x + 5} }}.{1 \over {{4^{{{\sin }^2}y}}}} \le 12sin2x−2sinx+5.4sin2y1≤1 also satisfy the equationAOption A. sin x = |sin y|BOption B. sin x = 2sin yCOption C. 2 sin x = sin yDOption D. 2 |sin x | = 3 sin yCheckSkip · show solution
