JEE Main 201912 Apr, Evening shiftMathematicsMediumIntegral Calculus369× since 2002A value of α\alphaα such that ∫αα+1dx(x+α)(x+α+1)=loge(98)\int\limits_\alpha ^{\alpha + 1} {{{dx} \over {\left( {x + \alpha } \right)\left( {x + \alpha + 1} \right)}}} = {\log _e}\left( {{9 \over 8}} \right)α∫α+1(x+α)(x+α+1)dx=loge(89) is :AOption A. 2BOption B. - 2COption C. 12{1 \over 2}21DOption D. −12-{1 \over 2}−21CheckSkip · show solution
