A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that AB(=a) subtends an angle of 60° at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30°. The height of the tower is:

Height and Distance: JEE Main 2007 Mathematics question

JEE Main 2007 · Annual, Paper 1 · Q3900

JEE Main 2007Annual, Paper 1MathematicsMediumHeight and Distance38× since 2004

A tower stands at the centre of a circular park.

A

and

B

are two points on the boundary of the park such that

AB(=a)

subtends an angle of

{60^ \circ }

at the foot of the tower, and the angle of elevation of the top of the tower from

A

B

{30^ \circ }

. The height of the tower is :

JEE Main 2007 Height and Distance Question with Solution (Annual Paper 1, Q3900) | JEE Arc