A thin uniform tube is bent into a circle of radius r in the vertical plane. Equal volumes of two immiscible liquids, whose densities are ρ ₁ and ρ ₂ (ρ ₁ > ρ ₂), fill half the circle. The angle θ between the radius vector passing through the common interface and the vertical is:

(C) θ = tan ⁻¹((ρ ₁ - ρ ₂)/(ρ ₁ + ρ ₂))

(A) θ = tan ⁻¹π ((ρ ₁)/(ρ ₂))

(B) θ = tan ⁻¹(π)/2((ρ ₁)/(ρ ₂))

(D) θ = tan ⁻¹(π)/2((ρ ₁ + ρ ₂)/(ρ ₁ - ρ ₂))

Properties of Solids and Liquids: JEE Main 2018 Physics question

JEE Main 2018 · 15 Apr, Morning shift · Q7978

JEE Main 201815 Apr, Morning shiftPhysicsHardProperties of Solids and Liquids184× since 2002

A thin uniform tube is bent into a circle of radius

r

in the vertical plane. Equal volumes of two immiscible liquids, whose densities are

{\rho _1}

and

{\rho _2}

\left( {{\rho _1} > {\rho _2}} \right),

fill half the circle. The angle

\theta

between the radius vector passing through the common interface and the vertical is :

JEE Main 2018 Properties of Solids and Liquids Question with Solution (15 Apr Morning shift, Q7978) | JEE Arc