A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of θ, where θ is the angle by which it has rotated, is given as k θ ². If its moment of inertia is I then the angular acceleration of the disc is:

Rotational Motion: JEE Main 2019 Physics question

JEE Main 2019 · 9 Apr, Morning shift · Q8089

JEE Main 20199 Apr, Morning shiftPhysicsMediumRotational Motion140× since 2002

A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of

\theta

, where

\theta

is the angle by which it has rotated, is given as k

\theta

². If its moment of inertia is I then the angular acceleration of the disc is :

JEE Main 2019 Rotational Motion Question with Solution (9 Apr Morning shift, Q8089) | JEE Arc