Electrostatics: JEE Main 2025 Physics question

JEE Main 2025 · 24 Jan, Evening shift · Q29

JEE Main 202524 Jan, Evening shiftPhysicsMediumElectrostatics167× since 2002

A small uncharged conducting sphere is placed in contact with an identical sphere but having

4\times10^{-8}

C charge and then removed to a distance such that the force of repulsion between them is

9\times10^{-3}

N. The distance between them is (Take

\frac{1}{4\pi\epsilon_0}

9\times10^{9}

in SI units)

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JEE Main 2025 Electrostatics Question with Solution (24 Jan Evening shift, Q29) | JEE Arc