A small point of mass m is placed at a distance 2R from the centre 'O' of a big uniform solid sphere of mass M and radius R. The gravitational force on 'm' due to M is F₁. A spherical part of radius R/3 is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of M is found to be F₂. The value of ratio F₁: F₂ is

Gravitation: JEE Main 2025 Physics question

JEE Main 2025 · 22 Jan, Morning shift · Q38

JEE Main 202522 Jan, Morning shiftPhysicsMediumGravitation159× since 2002

A small point of mass m is placed at a distance 2R from the centre 'O' of a big uniform solid sphere of mass M and radius R. The gravitational force on 'm' due to M is

F_1

. A spherical part of radius

R/3

is removed from the big sphere as shown in the figure and the gravitational force on m due to remaining part of M is found to be

F_2

. The value of ratio

F_1 : F_2

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JEE Main 2025 Gravitation Question with Solution (22 Jan Morning shift, Q38) | JEE Arc