Current Electricity: JEE Advanced 2023 Physics question

A series LCR circuit is connected to a $45 \sin (\omega t)$ Volt source. The resonant angular frequency of the circuit is $10^{5} \mathrm{rad} \mathrm{s}^{-1}$ and current amplitude at resonance is $I_{0}$. When the angular frequency of the source is $\omega=8 \times 10^{4} \mathrm{rad} \mathrm{s}^{-1}$, the current amplitude in the circuit is $0.05 I_{0}$. If $L=50 \mathrm{mH}$, match each entry in List-I with an appropriate value from List-II and choose the correct option. \textbf{List-I} (P) $I_{0}$ in $\mathrm{mA}$ (Q) The quality factor of the circuit (R) The bandwidth of the circuit in $\mathrm{rad} \mathrm{s}^{-1}$ (S) The peak power dissipated at resonance in Watt \textbf{List-II} (1) 44.4 (2) 18 (3) 400 (4) 2250 (5) 500