A series LCR circuit has L=0.01 H, R=10 Ω and C=1 μ F and it is connected to ac voltage of amplitude (V m) 50 ~V. At frequency 60% lower than resonant frequency, the amplitude of current will be approximately:

Electromagnetic Induction and Alternating Currents: JEE Main 2022 Physics question

JEE Main 2022 · 27 Jul, Evening shift · Q5910

JEE Main 202227 Jul, Evening shiftPhysicsMediumElectromagnetic Induction and Alternating Currents149× since 2002

A series LCR circuit has

\mathrm{L}=0.01\, \mathrm{H}, \mathrm{R}=10\, \Omega

and

\mathrm{C}=1 \mu \mathrm{F}

and it is connected to ac voltage of amplitude

\left(\mathrm{V}_{\mathrm{m}}\right) 50 \mathrm{~V}

. At frequency

60 \%

lower than resonant frequency, the amplitude of current will be approximately :