A satellite of mass M/2 is revolving around earth in a circular orbit at a height of R/3 from earth surface. The angular momentum of the satellite is M√(GMR/x). The value of x is _ _ _, where M and R are the mass and radius of earth, respectively. (G is the gravitational constant)

Gravitation: JEE Main 2025 Physics question

JEE Main 2025 · 23 Jan, Evening shift · Q50

JEE Main 202523 Jan, Evening shiftPhysicsMediumGravitation159× since 2002

A satellite of mass

\dfrac{M}{2}

is revolving around earth in a circular orbit at a height of

\dfrac{R}{3}

from earth surface. The angular momentum of the satellite is

M\sqrt{\dfrac{GMR}{x}}

. The value of

x

is ______, where M and R are the mass and radius of earth, respectively. (G is the gravitational constant)

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2025 Gravitation Question with Solution (23 Jan Evening shift, Q50) | JEE Arc