Electromagnetic Induction and Alternating Currents: JEE Main 2011 Physics question

JEE Main 2011 · Annual, Paper 1 · Q5946

JEE Main 2011Annual, Paper 1PhysicsMediumElectromagnetic Induction and Alternating Currents149× since 2002

A resistor

'R'

and

2\mu F

capacitor in series is connected through a switch to

200

V

direct supply. Across the capacitor is a neon bulb that lights up at

120

V.

Calculate the value of

R

to make the bulb light up

5

s

after the switch has been closed.

\left( {{{\log }_{10}}2.5 = 0.4} \right)

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JEE Main 2011 Electromagnetic Induction and Alternating Currents Question with Solution (Annual Paper 1, Q5946) | JEE Arc