JEE Main 2013Session, Shift 1MathematicsMediumCoordinate Geometry478× since 2002A ray of light along x+3y=3x + \sqrt 3 y = \sqrt 3x+3y=3 gets reflected upon reaching XXX-axis, the equation of the reflected ray is :AOption A. y=x+3y = x + \sqrt 3y=x+3BOption B. 3y=x−3\sqrt 3 y = x - \sqrt 33y=x−3COption C. y=3x−3y = \sqrt 3 x - \sqrt 3y=3x−3DOption D. 3y=x−1\sqrt 3 y = x - 13y=x−1CheckSkip · show solution
