A poly-atomic molecule (C V = 3R, C P = 4R, where R is gas constant) goes from phase space point A (P A = 10⁵ Pa, V A = 4 × 10⁻⁶ m³) to point B (P B = 5 × 10⁴ Pa, V B = 6 × 10⁻⁶ m³) to point C (P C = 10⁴ Pa, V C = 8 × 10⁻⁶ m³). A to B is an adiabatic path and B to C is an isothermal path. The net heat absorbed per unit mole by the system is:

Thermodynamics: JEE Main 2025 Physics question

JEE Main 2025 · 29 Jan, Evening shift · Q40

JEE Main 202529 Jan, Evening shiftPhysicsMediumThermodynamics163× since 2002

A poly-atomic molecule (

C_V = 3R

C_P = 4R

, where R is gas constant) goes from phase space point A (

P_A = 10^5

Pa,

V_A = 4 \times 10^{-6}

m³) to point B (

P_B = 5 \times 10^4

Pa,

V_B = 6 \times 10^{-6}

m³) to point C (

P_C = 10^4

Pa,

V_C = 8 \times 10^{-6}

m³). A to B is an adiabatic path and B to C is an isothermal path. The net heat absorbed per unit mole by the system is :

JEE Main 2025 Thermodynamics Question with Solution (29 Jan Evening shift, Q40) | JEE Arc