A point P moves so that the sum of squares of its distances from the points (1,2) and (-2,1) is 14. Let f(x, y)=0 be the locus of P, which intersects the x -axis at the points A, B and the y -axis at the points C, D. Then the area of the quadrilateral ACBD is equal to:

Coordinate Geometry: JEE Main 2022 Mathematics question

JEE Main 2022 · 26 Jul, Morning shift · Q5570

JEE Main 202226 Jul, Morning shiftMathematicsMediumCoordinate Geometry478× since 2002

A point

P

moves so that the sum of squares of its distances from the points

(1,2)

and

(-2,1)

is 14. Let

f(x, y)=0

be the locus of

\mathrm{P}

, which intersects the

x

-axis at the points

\mathrm{A}

\mathrm{B}

and the

y

-axis at the points C, D. Then the area of the quadrilateral ACBD is equal to :