Kinematics: JEE Main 2026 Physics question

JEE Main 2026 · 28 Jan, Evening shift · Q34

JEE Main 202628 Jan, Evening shiftPhysicsMediumKinematics177× since 2002

A particle starts moving from time

t = 0

and its coordinate is given as

x(t) = 4t^3 - 3t

. A. The particle returns to its original position (origin) 0.866 units later B. The particle is 1 unit away from origin at its turning point C. Acceleration of the particle is non-negative D. The particle is 0.5 units away from origin at its turning point E. Particle never turns back as acceleration is non-negative. Choose the correct answer from the options given below :

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JEE Main 2026 Kinematics Question with Solution (28 Jan Evening shift, Q34) | JEE Arc