A particle moves in x - y plane under the influence of a force F such that its linear momentum is p(t)=i cos (kt)-j sin (kt). If k is constant, the angle between F and p will be:

Laws of Motion: JEE Main 2024 Physics question

JEE Main 2024 · 5 Apr, Evening shift · Q7604

JEE Main 20245 Apr, Evening shiftPhysicsHardLaws of Motion70× since 2002

A particle moves in

x

y

plane under the influence of a force

\vec{F}

such that its linear momentum is

\overrightarrow{\mathrm{p}}(\mathrm{t})=\hat{i} \cos (\mathrm{kt})-\hat{j} \sin (\mathrm{kt})

. If

\mathrm{k}

is constant, the angle between

\overrightarrow{\mathrm{F}}

and

\overrightarrow{\mathrm{p}}

will be :

JEE Main 2024 Laws of Motion Question with Solution (5 Apr Evening shift, Q7604) | JEE Arc