JEE Main 2010Annual, Paper 1PhysicsMediumKinematics177× since 2002A particle is moving with velocity v→=k(yi^+xj^)\overrightarrow v = k\left( {y\widehat i + x\widehat j} \right)v=k(yi+xj), where K is a constant. The general equation for its path isAOption A. y = x² + constantBOption B. y² = x + constantCOption C. xy = constantDOption D. y² = x² + constantCheckSkip · show solution
