A particle executes simple harmonic motion with an amplitude of 4 ~cm. At the mean position, velocity of the particle is 10 ~cm / s. The distance of the particle from the mean position when its speed becomes 5 ~cm / s is √(α) ~cm, where α= _ _ _ _.

Oscillations and Waves: JEE Main 2024 Physics question

JEE Main 2024 · 27 Jan, Morning shift · Q76

JEE Main 202427 Jan, Morning shiftPhysicsMediumOscillations and Waves185× since 2002

A particle executes simple harmonic motion with an amplitude of

4 \mathrm{~cm}

. At the mean position, velocity of the particle is

10 \mathrm{~cm} / \mathrm{s}

. The distance of the particle from the mean position when its speed becomes

5 \mathrm{~cm} / \mathrm{s}

\sqrt{\alpha} \mathrm{~cm}

, where

\alpha=

________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2024 Oscillations and Waves Question with Answer (27 Jan Morning shift, Q76) | JEE Arc