A parallel plate capacitor of capacitance 2 ~F is charged to a potential V, The energy stored in the capacitor is E₁. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is E₂. The ratio E₂ / E₁ is:

Electrostatics: JEE Main 2023 Physics question

JEE Main 2023 · 11 Apr, Morning shift · Q6180

JEE Main 202311 Apr, Morning shiftPhysicsHardElectrostatics167× since 2002

A parallel plate capacitor of capacitance

2 \mathrm{~F}

is charged to a potential

\mathrm{V}

, The energy stored in the capacitor is

E_{1}

. The capacitor is now connected to another uncharged identical capacitor in parallel combination. The energy stored in the combination is

\mathrm{E}_{2}

. The ratio

\mathrm{E}_{2} / \mathrm{E}_{1}

is :

JEE Main 2023 Electrostatics Question with Solution (11 Apr Morning shift, Q6180) | JEE Arc