A natural number has prime factorization given by n = 2ˣ3^(y)5^(z), where y and z are such that y + z = 5 and y⁻¹ + z⁻¹ = 5/6, y > z. Then the number of odd divisions of n, including 1, is:

Permutations and Combinations: JEE Main 2021 Mathematics question

JEE Main 2021 · 26 Feb, Evening shift · Q4805

JEE Main 202126 Feb, Evening shiftMathematicsMediumPermutations and Combinations98× since 2002

A natural number has prime factorization given by n = 2^x3^y5^z, where y and z are such that y + z = 5 and y^

-

1 + z^

-

1 =

{5 \over 6}

, y > z. Then the number of odd divisions of n, including 1, is :

JEE Main 2021 · 26 Feb, Evening shift · Q4805

JEE Main 202126 Feb, Evening shiftMathematicsMediumPermutations and Combinations98× since 2002

A natural number has prime factorization given by n = 2^x3^y5^z, where y and z are such that y + z = 5 and y^

-

1 + z^

-

1 =

{5 \over 6}

, y > z. Then the number of odd divisions of n, including 1, is :