JEE Main 20207 Jan, Evening shiftPhysicsMediumLaws of Motion70× since 2002
A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied
horizontally at the mid point of the rope such that the top half of the rope makes an angle of 45^o
with the vertical. Then F equal : (Take g = 10 ms^–2 and the rope to be massless)