JEE Main 2003Annual, Paper 1PhysicsEasyLaws of Motion70× since 2002A marble block of mass 222 kgkgkg lying on ice when given a velocity of 666 m/sm/sm/s is stopped by friction in 101010 s.s.s. Then the coefficient of friction isAOption A. 0.020.020.02BOption B. 0.030.030.03COption C. 0.040.040.04DOption D. 0.060.060.06CheckSkip · show solution
