JEE Main 202431 Jan, Morning shiftPhysicsMediumUnits and Measurements122× since 2002A force is represented by F=ax2+bt12F=a x^2+b t^{\frac{1}{2}}F=ax2+bt21 where x=x=x= distance and t=t=t= time. The dimensions of b2/ab^2 / ab2/a are:AOption A. [ML2 T−3]\left[\mathrm{ML}^2 \mathrm{~T}^{-3}\right][ML2 T−3]BOption B. [ML3 T−3]\left[\mathrm{ML}^3 \mathrm{~T}^{-3}\right][ML3 T−3]COption C. [MLT−2]\left[M L T^{-2}\right][MLT−2]DOption D. [ML−1T−1]\left[M L^{-1} T^{-1}\right][ML−1T−1]CheckSkip · show solution
