Work, Energy and Power: JEE Main 2025 Physics question

JEE Main 2025 · 23 Jan, Morning shift · Q46

JEE Main 202523 Jan, Morning shiftPhysicsMediumWork, Energy and Power70× since 2002

A force

\vec f=x^2y\hat i+y^2\hat j

acts on a particle in a plane

x+y=10

. The work done by this force during a displacement from (0, 0) to (4m, 2m) is ____ Joule (round off to the nearest integer)

Your answerInteger or decimal

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JEE Main 2025 Work, Energy and Power Question with Solution (23 Jan Morning shift, Q46) | JEE Arc

JEE Main 2025 · 23 Jan, Morning shift · Q46

JEE Main 202523 Jan, Morning shiftPhysicsMediumWork, Energy and Power70× since 2002

A force

\vec f=x^2y\hat i+y^2\hat j

acts on a particle in a plane

x+y=10

. The work done by this force during a displacement from (0, 0) to (4m, 2m) is ____ Joule (round off to the nearest integer)

Your answerInteger or decimal