A current of 5 A is passing through a non-linear magnesium wire of cross-section 0.04 m². At every point the direction of current density is at an angle of 60° with the unit vector of area of cross-section. The magnitude of electric field at every point of the conductor is: (Resistivity of magnesium ρ = 44 × 10⁻⁸ Ω m)

Current Electricity: JEE Main 2021 Physics question

JEE Main 2021 · 20 Jul, Morning shift · Q6400

JEE Main 202120 Jul, Morning shiftPhysicsMediumCurrent Electricity150× since 2002

A current of 5 A is passing through a non-linear magnesium wire of cross-section 0.04 m². At every point the direction of current density is at an angle of 60

^\circ

with the unit vector of area of cross-section. The magnitude of electric field at every point of the conductor is : (Resistivity of magnesium

\rho

= 44

\times

10^

-

\Omega

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