A coil of self inductance 10 mH and resistance 0.1 Ω is connected through a switch to a battery of internal resistance 0.9 Ω. After the switch is closed, the time taken for the current to attain 80% of the saturation value is: [take ln 5 = 1.6]

Electromagnetic Induction and Alternating Currents: JEE Main 2019 Physics question

JEE Main 2019 · 10 Apr, Evening shift · Q5947

JEE Main 201910 Apr, Evening shiftPhysicsMediumElectromagnetic Induction and Alternating Currents149× since 2002

A coil of self inductance 10 mH and resistance 0.1

\Omega

is connected through a switch to a battery of internal resistance 0.9

\Omega

. After the switch is closed, the time taken for the current to attain 80% of the saturation value is: [take ln 5 = 1.6]

JEE Main 2019 Electromagnetic Induction and Alternating Currents Question with Solution (10 Apr Evening shift, Q5947) | JEE Arc

JEE Main 2019 · 10 Apr, Evening shift · Q5947

JEE Main 201910 Apr, Evening shiftPhysicsMediumElectromagnetic Induction and Alternating Currents149× since 2002

A coil of self inductance 10 mH and resistance 0.1

\Omega

is connected through a switch to a battery of internal resistance 0.9

\Omega

. After the switch is closed, the time taken for the current to attain 80% of the saturation value is: [take ln 5 = 1.6]