A cell of emf 90 V is connected across series combination of two resistors each of 100 Ω resistance. A voltmeter of resistance 400 Ω is used to measure the potential difference across each resistor. The reading of the voltmeter will be:

Current Electricity: JEE Main 2023 Physics question

JEE Main 2023 · 24 Jan, Evening shift · Q6476

JEE Main 202324 Jan, Evening shiftPhysicsMediumCurrent Electricity150× since 2002

A cell of emf 90 V is connected across series combination of two resistors each of 100

\Omega

resistance. A voltmeter of resistance 400

\Omega

is used to measure the potential difference across each resistor. The reading of the voltmeter will be :

JEE Main 2023 Current Electricity Question with Solution (24 Jan Evening shift, Q6476) | JEE Arc

JEE Main 2023 · 24 Jan, Evening shift · Q6476

JEE Main 202324 Jan, Evening shiftPhysicsMediumCurrent Electricity150× since 2002

A cell of emf 90 V is connected across series combination of two resistors each of 100

\Omega

resistance. A voltmeter of resistance 400

\Omega

is used to measure the potential difference across each resistor. The reading of the voltmeter will be :