A capacitor of capacitance 150.0 ~μ F is connected to an alternating source of emf given by E=36 sin (120 π t) V. The maximum value of current in the circuit is approximately equal to:

Electromagnetic Induction and Alternating Currents: JEE Main 2023 Physics question

JEE Main 2023 · 6 Apr, Evening shift · Q5921

JEE Main 20236 Apr, Evening shiftPhysicsMediumElectromagnetic Induction and Alternating Currents149× since 2002

A capacitor of capacitance

150.0 ~\mu \mathrm{F}

is connected to an alternating source of emf given by

\mathrm{E}=36 \sin (120 \pi \mathrm{t}) \mathrm{V}

. The maximum value of current in the circuit is approximately equal to :

JEE Main 2023 · 6 Apr, Evening shift · Q5921

JEE Main 20236 Apr, Evening shiftPhysicsMediumElectromagnetic Induction and Alternating Currents149× since 2002

A capacitor of capacitance

150.0 ~\mu \mathrm{F}

is connected to an alternating source of emf given by

\mathrm{E}=36 \sin (120 \pi \mathrm{t}) \mathrm{V}

. The maximum value of current in the circuit is approximately equal to :