A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of 30° with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground? [ g = 10m/s², sin 30° = 1/2, cos 30° = (3)/2 ]

Kinematics: JEE Main 2003 Physics question

JEE Main 2003 · Annual, Paper 1 · Q7772

JEE Main 2003Annual, Paper 1PhysicsMediumKinematics177× since 2002

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of

30^\circ

with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground?

\left[ {g = 10m/{s^2},\sin 30^\circ = {1 \over 2},\cos 30^\circ = {{\sqrt 3 } \over 2}} \right]

JEE Main 2003 Kinematics Question with Solution (Annual Paper 1, Q7772) | JEE Arc

JEE Main 2003 · Annual, Paper 1 · Q7772

JEE Main 2003Annual, Paper 1PhysicsMediumKinematics177× since 2002

A boy playing on the roof of a 10 m high building throws a ball with a speed of 10 m/s at an angle of

30^\circ

with the horizontal. How far from the throwing point will the ball be at the height of 10 m from the ground?

\left[ {g = 10m/{s^2},\sin 30^\circ = {1 \over 2},\cos 30^\circ = {{\sqrt 3 } \over 2}} \right]