A ball is spun with angular acceleration α = 6t² - 2t where t is in second and α is in rads⁻². At t = 0, the ball has angular velocity of 10 rads⁻¹ and angular position of 4 rad. The most appropriate expression for the angular position of the ball is:

(B) (t⁴)/2 - (t³)/3 + 10t + 4

(C) (2t⁴)/3 - (t³)/6 + 10t + 12

Rotational Motion: JEE Main 2022 Physics question

JEE Main 2022 · 28 Jun, Evening shift · Q8073

JEE Main 202228 Jun, Evening shiftPhysicsMediumRotational Motion140× since 2002

A ball is spun with angular acceleration

\alpha

= 6t²

-

2t where t is in second and

\alpha

is in rads^

-

2. At t = 0, the ball has angular velocity of 10 rads^

-

1 and angular position of 4 rad. The most appropriate expression for the angular position of the ball is :

JEE Main 2022 Rotational Motion Question with Solution (28 Jun Evening shift, Q8073) | JEE Arc