JEE Main 202430 Jan, Evening shiftChemistryMediump-Block Elements95× since 2002A and B formed in the following reactions are: CrO2Cl2+4NaOH→A+2NaCl+2H2O,A+2HCl+2H2O2→B+3H2O\begin{aligned} & \mathrm{CrO}_2 \mathrm{Cl}_2+4 \mathrm{NaOH} \rightarrow \mathrm{A}+2 \mathrm{NaCl}+2 \mathrm{H}_2 \mathrm{O}, \\ & \mathrm{A}+2 \mathrm{HCl}+2 \mathrm{H}_2 \mathrm{O}_2 \rightarrow \mathrm{B}+3 \mathrm{H}_2 \mathrm{O} \end{aligned}CrO2Cl2+4NaOH→A+2NaCl+2H2O,A+2HCl+2H2O2→B+3H2OAOption A. A=Na2Cr2O7, B=CrO5\mathrm{A}=\mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7, \mathrm{~B}=\mathrm{CrO}_5A=Na2Cr2O7, B=CrO5BOption B. A=Na2CrO4, B=CrO5\mathrm{A}=\mathrm{Na}_2 \mathrm{CrO}_4, \mathrm{~B}=\mathrm{CrO}_5A=Na2CrO4, B=CrO5COption C. A=Na2Cr2O4, B=CrO4\mathrm{A}=\mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_4, \mathrm{~B}=\mathrm{CrO}_4A=Na2Cr2O4, B=CrO4DOption D. A=Na2Cr2O7, B=CrO3\mathrm{A}=\mathrm{Na}_2 \mathrm{Cr}_2 \mathrm{O}_7, \mathrm{~B}=\mathrm{CrO}_3A=Na2Cr2O7, B=CrO3CheckSkip · show solution
