Electrostatics: JEE Main 2020 Physics question

JEE Main 2020 · 2 Sep, Evening shift · Q6140

JEE Main 20202 Sep, Evening shiftPhysicsMediumElectrostatics167× since 2002

A 10

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F capacitor is fully charged to a potential difference of 50 V. After removing the source voltage it is connected to an uncharged capacitor in parallel. Now the potential difference across them becomes 20 V. The capacitance of the second capacitor is :

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JEE Main 2020 Electrostatics Question with Solution (2 Sep Evening shift, Q6140) | JEE Arc