6/(3¹²) + 10/(3¹¹) + 20/(3¹⁰) + 40/(3⁹) +... + 10240/3 = 2ⁿ. m, where m is odd, then m. n is equal to _ _ _ _ _ _.

Sequence and Series: JEE Main 2022 Mathematics question

JEE Main 2022 · 28 Jul, Evening shift · Q47

JEE Main 202228 Jul, Evening shiftMathematicsMediumSequence and Series179× since 2002

{6 \over {{3^{12}}}} + {{10} \over {{3^{11}}}} + {{20} \over {{3^{10}}}} + {{40} \over {{3^9}}} + \,\,...\,\, + \,\,{{10240} \over 3} = {2^n}\,.\,m

, where m is odd, then m . n is equal to ____________.

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2022 · 28 Jul, Evening shift · Q47

JEE Main 202228 Jul, Evening shiftMathematicsMediumSequence and Series179× since 2002

{6 \over {{3^{12}}}} + {{10} \over {{3^{11}}}} + {{20} \over {{3^{10}}}} + {{40} \over {{3^9}}} + \,\,...\,\, + \,\,{{10240} \over 3} = {2^n}\,.\,m

, where m is odd, then m . n is equal to ____________.

Your answerType your answer. Integers and decimals are accepted.