1 × 10⁻⁵ ~M ~AgNO₃ is added to 1 ~L of saturated solution of AgBr. The conductivity of this solution at 298 ~K is _ _ _ _ _ _ _ × 10⁻⁸ ~S ~m⁻¹. [Given: K SP (AgBr)=4.9 × 10⁻¹³ at 298 ~K λ Ag⁺ ⁰=6 × 10⁻³ ~S ~m² ~mol⁻¹ λ Br⁻ ⁰=8 × 10⁻³ ~S ~m² ~mol⁻¹.λ N O₃⁻⁰=7 × 10⁻³ ~S ~m² ~mol⁻¹]

Redox Reactions and Electrochemistry: JEE Main 2023 Chemistry question

JEE Main 2023 · 1 Feb, Evening shift · Q10

JEE Main 20231 Feb, Evening shiftChemistryHardRedox Reactions and Electrochemistry138× since 2002

1 \times 10^{-5} ~\mathrm{M} ~\mathrm{AgNO}_{3}

is added to

1 \mathrm{~L}

of saturated solution of

\mathrm{AgBr}

. The conductivity of this solution at

298 \mathrm{~K}

is _____________

\times 10^{-8} \mathrm{~S} \mathrm{~m}^{-1}

. [Given :

\mathrm{K}_{\mathrm{SP}}(\mathrm{AgBr})=4.9 \times 10^{-13}

298 \mathrm{~K}

\begin{aligned} & \lambda_{\mathrm{Ag}^{+}}^{0}=6 \times 10^{-3} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1} \\ & \lambda_{\mathrm{Br}^{-}}^{0}=8 \times 10^{-3} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1} \\ & \left.\lambda_{\mathrm{NO}_{3}^{-}}^{0}=7 \times 10^{-3} \mathrm{~S} \mathrm{~m}^{2} \mathrm{~mol}^{-1}\right] \end{aligned}

Your answerType your answer. Integers and decimals are accepted.