1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27^(°) C. The work done is 3 ~kJ ~mol⁻¹. The final temperature of the gas is _ _ _ _ K (Nearest integer). Given C V =20 ~J ~mol⁻¹ ~K⁻¹

Chemical Thermodynamics: JEE Main 2023 Chemistry question

JEE Main 2023 · 30 Jan, Evening shift · Q21

JEE Main 202330 Jan, Evening shiftChemistryMediumChemical Thermodynamics84× since 2002

1 mole of ideal gas is allowed to expand reversibly and adiabatically from a temperature of

27^{\circ} \mathrm{C}

. The work done is

3 \mathrm{~kJ} \mathrm{~mol}^{-1}

. The final temperature of the gas is ________

\mathrm{K}

(Nearest integer). Given

\mathrm{C_V}=20 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}

Your answerType your answer. Integers and decimals are accepted.

JEE Main 2023 Chemical Thermodynamics Question with Answer (30 Jan Evening shift, Q21) | JEE Arc